Question

One positive number is 4 more than twice another. Their product is 198

Answer 1

Answer:

22 and 9

Step-by-step explanation:

Let the positive number be x.

Let the other number be y.

x = 2y + 4

xy = 198

Substitute x as 2y + 4 in the second equation.

(2y+4)y = 198

2y² + 4y = 198

2y² + 4y - 198 = 0

2(y-9)(y+11) = 0

y-9=0 or y+11=0

y=9

y=-11

The product is 198, so y is positive.

x(9)=198

x=22

Answer 2

Answer:

$\large \boxed{\sf \ \ 9 \text{ and } 22 \ \ }$

Step-by-step explanation:

Hello,

We can write that, x being the second number

(4 + 2*x) *x = 198

Let's solve this equation.

$(4+2x)x=198\\\\4x+2x^2=198 \\\\\text{*** subtract 198 from both sides ***}\\\\2x^2+4x-198 = 0\\\\\text{*** The product of the zeroes is -198/2=-99=-11*9 and their sum is -4/2=-2 ***}\\\\2x^2+4x-198=2(x-9)(x+11)=0\\\\x=9 \ \ or \ \ x=-11$

We are looking for positive number so the solution is 9.

And the first number is 4 + 2 * 9 = 4 + 18 = 22

Hope this helps.

Do not hesitate if you need further explanation.

Thank you