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ser-zykov [4K]
3 years ago
15

What are the zeroes of f(x) = x2 + 5x + 6?

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

Zeros are x = −2, −3 .

Step-by-step explanation:

Given : f(x) = x² + 5x + 6.

To find : What are the zeroes of f(x).

Solution : We have given that

f(x) = x² + 5x + 6.

To find the zeros of the function we need to set f(x) = 0.

x² + 5x + 6 = 0.

On factoring

x² + 3x +2x + 6 = 0.

Taking common x from first two term and 2 from last two terms

x ( x + 3) +2 ( x +3) = 0.

On grouping

(x + 3) (x + 2)  = 0

Now, x + 3 = 0   and x + 2 = 0

x = -3 and x = -2

Therefore, Zeros are x = −2, −3 .

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Explain to me the rule of pemdas in order of operations.
Alborosie
Parenthesis
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multiplication/division
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when given a math problem you must go through these operations from top to bottom to recieve the correct answer
7 0
3 years ago
Read 2 more answers
If log2 5 = a, log2 3 = b and log2 7 = c, determine an expression for log2 (25/21) in terms of a, b, and c
Ilia_Sergeevich [38]

Answer:

2a - b -c

Step-by-step explanation: We know that:

log_{2} 5 = a\\log_{2} 3 = b\\log_2 7 = c\\

and we want:

log_2 \frac{25}{21}.

We can form the numerator using just the first fact (since 5^2 is 25) and the denominator using the latter two (since 3*7 = 21).

log_2 \frac{25}{21} = log_2 \frac{5^2}{3*7}.

The logarithm of a division can be expanded by subtracting the numerator and denominator (while still keeping the log). The logarithm of a product can be expanded by adding the terms while keeping the log. If the logarithm is raised to a power, we can bring it down as a factor:

log_2 \frac{5^2}{3*7} = log_2(5)^2 - log_2 (3*7) = 2 log_2(5) - (log_2 3 + log_2 7)

= 2 log_2(5) - log_2 3 - log_2 7 .

Substituting the variables:

2 log_2(5) - log_2 3 - log_2 7 = 2a - b - c

8 0
3 years ago
Is it possible to arrange 152 books on a shelf so that the first shelf has 7 fewer books than the second shelf and 11 more than
Zepler [3.9K]

Using a system of equations, it is found that <u>since the solution of the system does not involve decimal numbers</u>, it is possible to arrange the books in this way.

For the system, we consider that:

  • x is the number of books on the first shelf.
  • y is the number of books on the second shelf.
  • z is the number of books on the third shelf.

In total, there are 152 books, hence:

x + y + z = 152

The first shelf has 7 fewer books than the second shelf, hence:

x = y - 7

Also, it has 11 more books than the third shelf, hence:

x = z + 11

Then:

y - 7 = z + 11

z = y - 18

Then, replacing in the first equation:

x + y + z = 152

y - 7 + y + y - 18 = 152

3y = 177

y = \frac{177}{3}

y = 59

The number of books in each shelf has to be countable, that is, cannot be decimal.

  • Then, <u>since the solution of the system does not involve decimal numbers</u>, it is possible to arrange the books in this way.

To learn more about system of equations, you can take a look at brainly.com/question/14183076

7 0
2 years ago
Ethan buys a video game on sale. If the video game usually costs $39.99, and it was on sale for 20% off, how much did Ethan pay?
Ann [662]
Hello There!

Ethan would pay $31.99  or rounded up two 32 which ever is your answer choice 

Thus being why.

if you times 39.99 x .20 you get 7.998

39.99 - 7.998 is 31.99

Hope This Helps!
7 0
4 years ago
Read 2 more answers
4/5 minus 1/3 plz i need help
IRISSAK [1]

Answer:

7/15

Step-by-step explanation:

Step 1

We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change, too. They get multiplied by the other term's denominator.

So we multiply 4 by 3, and get 12.

Then we multiply 1 by 5, and get 5.

Next we give both terms new denominators -- 5 × 3 = 15.

So now our fractions look like this:

12

15

−  

5

15

Step 2

Since our denominators match, we can subtract the numerators.

12 − 5 = 7

So the answer is:

7

15

Step 3

Last of all, we need to simplify the fraction, if possible. Can it be reduced to a simpler fraction?

To find out, we try dividing it by 2...

Nope! So now we try the next greatest prime number, 3...

Nope! So now we try the next greatest prime number, 5...

Nope! So now we try the next greatest prime number, 7...

Nope! So now we try the next greatest prime number, 11...

No good. 11 is larger than 7. So we're done reducing.

6 0
3 years ago
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