All categories

2 years ago

For the following, write an equivalent expression in standard form: (5x2 + 6x - 2) + 4x (3x – 7).

Mathematics

1 answer:

Roman55 [17]2 years ago

7 0

Answer:

17x^2 -22x -2

Step-by-step explanation:

5x^2 +6x -2 +4x (3x-7)
5x^2 +6x -2 +12x^2 -28x
17x^2 +6x -2 -28x
Answer: 17x^2 -22x -2

Just so you know when I put (^) the number after it is a exponent.

You might be interested in

Jfifickxjcicixkskekeidixixjx

777dan777 [17]

Wjdhiqhdydhhwjebfksomern
Enchiladas

6 0

2 years ago

F triangle DEF is translated 6 units to the left, what are the coordinates of point D′ in the image?

kati45 [8]

The answer is -5,2 !!!!!!!

3 0

2 years ago

Find the measure of the indicated angel.

schepotkina [342]

Answer:

Step-by-step explanation:

44+32=76

180-76=104

104+36=140

180-140=40

D)40

8 0

2 years ago

(2.9X10^5)X(3.4X10^3 in standard form

Evgesh-ka [11]

By using exponent, it can be verified that

$(2.9 \times 10^5) \times (3.4 \times 10^3)$ in standard form is $9.86 \times 10^8$

What are exponent?

Exponent tells us how many times a number is multiplied by itself.

For example : In $2^4 = 2 \times 2 \times 2 \times 2$

Here, 2 is multiplied by itself 4 times.

If $a^m = a \times a \times a ... \times a$ (m times), a is the base and m is the index.

The laws of index are

$a^{m + n} = a^m \times a^n\\a^{m - n} = \frac{a^m}{a^n}\\(\frac{a}{b})^m = \frac{a^m}{b^m}\\(ab)^m = a^m b^m\\a^0 = 1\\a^{-n} = \frac{1}{a^n}$

The given exponent is

$(2.9 \times 10^5) \times (3.4 \times 10^3)\\9.86 \times 10^{5+ 3}\\9.86 \times 10^8$

To learn more about exponent, refer to the link:

brainly.com/question/11975096

#SPJ1

8 0

1 year ago

Find all the values of x in the set of complex numbers that satisfy the following equation:

Fynjy0 [20]

Compute all the component integrals first:

$I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)$
$I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)$
$I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi$

Now,

$\sqrt2\approx1.4\implies \sqrt2+1\approx2.4$
$\implies \left\lceil I_1\right\rceil=2$

$e$
$\implies\left\lfloor I_2\right\rfloor=-1$

$\pi\approx3.14\implies\left\lceil I_3\right\rceil=4$

So the given equation reduces to

$\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!$
$\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23$
$4x^3+3x^2+2x+24=0$

a fairly standard cubic. Incidentally, when $x=-2$ , the LHS reduces to 0, so $x+2$ is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.

5 0

2 years ago