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Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence
.
- Equally as likely to be a boy or a girl, hence
.
The probability of one of each is P(X = 1), hence:
0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377
The simplified form of the equation is 4.4x + 1.5.
Given
Equation; (1.6x + 7.3) + (–0.6x + 2) – (7.8 – 3.4x)
<h3>Addition</h3>The addition is the process of adding things together.
To simplify the equation follow all the steps given below.
First, open the brackets combine like terms, and simplify.
Then,
The equation in simplified form is;
Hence, the simplified form of the equation is 4.4x + 1.5.
To know more about addition click the link given below.