A) The solutions to this set of equation is where the graphs cross. They cross at point (-3, -2).
B) The solutions for f(x) would be points that fall on the graph of f(x). Two possible points are (-3, -2) and (-7, 3)
C) These 2 functions cross at (4, 1). That is the solution.
A.) $15 would seem like it would be right
For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
Answer:
m=8
Step-by-step explanation:
-88=-3(4m+5)-(1-3m)
-88=-12m-15-(1-3m) <- Distributive Property
-88=-12m-15-1+3m <- Open () if there is a negative negative the symbol equals positive
-88=-9m-16 <- Simplify
0=-9m+72 <- Add 88 to both sides
9m = 72 <- Add 9m to both sides
9m = 72
/9 /9
m=8
