For this case we have the following equations that represent the position of the rocket: x (t) = 3t y (t) = 4t ^ 2 + 1 Substituting t = 10 in both equations we have: x (10) = 3 (10) = 30 y (10) = 4 (10) ^ 2 + 1 = 400 + 1 = 401 Therefore, the position of the rocket is: (x, y) = (30, 401) Answer: the ship after 10 seconds is at: C.) (30,401)