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artcher [175]
3 years ago
13

Is this in quadratic form x^4-6x^2-27=0

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

what the heck is this

Step-by-step explanation:

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Simplify.<br><br> 4a(6) + 3a<br><br> 27a<br> 27a2<br> 24a2 + 3a<br> 13a
svp [43]

4a(6)+3a=(4)(6)a+3a=24a+3a=(24+3)a=27a

4 0
3 years ago
What is half of the fraction 3/4
schepotkina [342]
The half of 3/4 is 0.375, or 3/8. All you have to do is multiply 3/4 times 1/2. 
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3 years ago
The temperature is 1°C below zero.
Alenkasestr [34]

Answer:

-1 is the answer :)

5 0
3 years ago
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Salsk061 [2.6K]

Answer:

The sample size must be greater than or equal to 756

Step-by-step explanation:

The formula to calculate the error of the proportion is the following

E=z_{\alpha/2}*\sqrt{\frac{p(1-p)}{n}}

where p is the proportion, n the sample size, E is the error and z is the z-score for a confidence level of 95%

For a confidence level of 95% z_{\alpha/2}=1.96

We know that for this case p=0.23

We require that the error be 0.03 as maximum

Therefore we solve for the variable n

z_{\alpha/2}*\sqrt{\frac{p(1-p)}{n}}\leq0.03\\\\1.96*\sqrt{\frac{0.23(1-0.23)}{n}}\leq0.03\\\\\sqrt{\frac{0.23(1-0.23)}{n}}\leq \frac{0.03}{1.96}\\\\(\sqrt{\frac{0.23(1-0.23)}{n}})^2\leq (\frac{0.03}{1.96})^2\\\\\frac{0.23(1-0.23)}{n}\leq (\frac{0.03}{1.96})^2\\\\\frac{0.23(1-0.23)}{(\frac{0.03}{1.96})^2}\leq n\\\\n\geq\frac{0.23(1-0.23)}{(\frac{0.03}{1.96})^2}\\\\n\geq756

5 0
3 years ago
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**HELP!!! 30 POINTS, WILL GIVE BRAINLIEST**
Rama09 [41]

Answer:

a

Step-by-step explanation:

right

7 0
3 years ago
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