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tino4ka555 [31]
3 years ago
12

Plz help in the picture below plz ill give you brainliestt

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

change both the fractions to improper fractions. the area will be 147/4 , and the width will be 9/2 . with both of these you may now divide, (147/4) / (9/2)

remember to use the KCF when dividing fractions.

147 * 2 = 294

4 * 9 = 36

your new fraction will be 294/36 .... which it is also 8 1/6

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AveGali [126]
2,600 is the answer to your question
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Find the 72nd term of the arithmetic sequence -27, -11, 5, ...
MAXImum [283]

Step-by-step explanation:

first identify the common difference

The first term which i will define by u⁰=-27

u¹=u⁰+(1)d where d is the common difference and u¹ is the second term

u¹=-27+d

-11=-27+d

d=27-11=16

The 72nd term would be u⁷¹ since we started from u⁰ as our first term:

Use the explicit relation given by:

u(n)=u⁰+(n)d

u(71)=-27+71(d)

u⁷¹=-27+71(16)

u⁷¹=-27+1136

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8 0
3 years ago
Evaluate.
harina [27]

Answer:

I got .96

Step-by-step explanation:

2+23 is 25. 25 devided by 12 is .48. Times that by 2 and you get . 96. clearly that's not an option though so I'm not sure. sorry. did you make a typo by any chance?

3 0
2 years ago
Read 2 more answers
What is the circumference of the circle?
True [87]

Step-by-step explanation:

What is the circumference of the circle?

f) 52 cm2

e) 2610 cm2

5 0
3 years ago
The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po
grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm


Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

=xy

we are given that area as 1536

so, we can set it to 1536

xy=1536

now, we can solve for y

y=\frac{1536}{x}

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

A=(8+x+8)\times (12+y+12)

A=(x+16)\times (y+24)

now, we can plug back y

A=(x+16)\times (\frac{1536}{x}+24)

now, we have to minimize A

so, we will find derivative

A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)

we can use product rule

A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)

now, we can simplify it

A'=-\frac{24576}{x^2}+24

now, we can set it to 0

and then we can solve for x

A'=-\frac{24576}{x^2}+24=0

-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2

-24576+24x^2=0

x=32,\:x=-32

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

x=32

now, we can solve for y

y=\frac{1536}{32}

y=48

so, dimensions of printed poster are

length is 32 cm

width is 48 cm


5 0
3 years ago
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