The hour hand is 30 mm hope this is right
Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
It’s c since the line goes down 5 and the y intercept is 3 so it would be y=-5x+3
I don't either it is quite hard to be fair
Answer:
They are both similar in the way that the formula is base multiplied by height. They are different because of the type of shape on the base.
Step-by-step explanation:
hope this helps
