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3 years ago

13

Jeremy says that if you translate, rotate, or reflect a polygon, the area of the image is the same as the area of the original f

igure. Do you agree or disagree? Explain your choice.

1 answer:

lions [1.4K]3 years ago

3 0

Answer:

yes

Step-by-step explanation:

as long as the polygon is not dilated or the size of the polygon is not changed in any way, the area should stay the same.

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Mason Painting Services has a weekly payroll of $28,000. December 31 falls on Wednesday and Mason will pay its employees the fol

Inga [223]

28000 / 5 days = $5,600 per day

Wednesday, Thursday, Friday = 3 days.

5,600 x 3 days = $16,800

The amount should be $16,800

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3 years ago

What is the quotient (2x^2 + 12x +18 ) divided by (x +3)

katen-ka-za [31]

2(x^2+6x+9) = 2(x+3)^2

So after divided by (x+3), answer will be:

2(x+3)

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3 years ago

Please find the rule on how the triangles are congruent.

Yakvenalex [24]

Answer:

SAS (number 4)

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3 years ago

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jeka94

Answer:

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Step-by-step explanation:

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3 years ago

In the third week of July, a random sample of 40 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. A

suter [353]

Answer:

a. [6.6350,7.3950]

b. ME=0.5150

Step-by-step explanation:

a. Given that n=40, $\bar x=6.88$ and that: $z_{\alpha/2}=z_{0.05}=1.645$

The required 90% confidence interval can be calculated as:

$\bar x\pm(margin \ of \ error)\\\\\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\6.88\pm(1.645\times \frac{1.98}{\sqrt{40}})\\\\=[6.3650,7.3950]$

Hence, the 90% confidence interval for the population mean cash value of this crop is [6.6350,7.3950]

b. The margin of error at 90% confidence interval is calculated as:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\=(1.645\times \frac{1.98}{\sqrt{40}})\\\\=0.5150$

Hence, the margin of error is 0.5150

8 0

3 years ago