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Bad White [126]
3 years ago
12

Find the unit rate for 50 miles on 2 1/2 gallons

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
Unit rate is miles per 1 gallon
50mi/2 and 1/2 gallon
50mi/2.5 gallon
times 10/10
500mi/25 gallon
20mi/1gallon

answer is 20mi/gal
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The diameter of a circle is 14 in. Find its area in terms of
Luda [366]

Answer:

Given - Diameter of circle = 14 in

To find - Area of circle

Solution -

Diameter= 2 × Radius

14 = 2 × R

14/2 = R

7 = R

Area of circle= π r^²

22/7 × 7 × 7

22 × 7

154

7 0
3 years ago
If a square has an area of 225 square feet what is the length of each side
sdas [7]
The area of the square: A=a^2

where "a" is a length of side.


Therefore:
A=225\ ft^2\ and\ A=a^2\Rightarrow a^2=225\Rightarrow a=\sqrt{225}\Rightarrow \boxed{a=15\ (ft)}
3 0
3 years ago
Plz help I have no idea how to answer it​
saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please​
Ilya [14]

We know that the line is tangent at the point (2,8)

The derivative of the function at x=2 is

f'(x) = 6-2x \implies f'(2) = 6-4=2

So, the tangent line passes through the point (2,8) and has slope 2. The equation is

y-8 = 2(x-2) \iff y = 2x+4

This line crosses the x axis where y=0:

0 = 2x+4 \iff 2x = -4 \iff x = -2

6 0
3 years ago
Do you guys get <br> thank you
Levart [38]
On the tens one shade in 3 bars representig 3/10 kn the hunderes one shade in 30 squares
4 0
3 years ago
Read 2 more answers
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