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Bad White [126]
3 years ago
12

Find the unit rate for 50 miles on 2 1/2 gallons

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
Unit rate is miles per 1 gallon
50mi/2 and 1/2 gallon
50mi/2.5 gallon
times 10/10
500mi/25 gallon
20mi/1gallon

answer is 20mi/gal
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The box plots show the math scores of students in two different classes:
mezya [45]

Answer:

1st statement

Step-by-step explanation:

The line inside the box is the median.
Since in Class A the median line is on around 80 whilst Class B's median is 75.

So Median of

Class A > Class B

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2 years ago
How many solutions does the system have? y=3x+3 y=-2x+3
STatiana [176]

Answer:

One solution (0, 3).

Step-by-step explanation:

As both expressions in x are equal to y:

3x + 3 = -2x + 3

3x + 2x = 3 - 3

5x = 0

x =0.

So y = 3(0) + 3 = 3.

8 0
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Step-by-step explanation:

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2 years ago
2+2(560)+5638+163936
dmitriy555 [2]

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8 0
3 years ago
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A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
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