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inysia [295]
3 years ago
15

What two consecutive numbers have a sum of 53? Thanks! :P

Mathematics
2 answers:
zaharov [31]3 years ago
6 0
The numbers 26 and 27 are consecutive and have a sum of 53
Musya8 [376]3 years ago
4 0
Let's the name the first number x and the consecutive number x + 1. The sum of both of these numbers equals to 53.

We now have our equation:

x + x + 1 = 53

Now solve for x.

x + x + 1 = 53
2x + 1 = 53 <-- Combine like terms
2x = 52 <-- Subtract 1 from each side
x = 26

So, the first number is 26 and the second number is 27.
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What are the next three terms in the sequence 4, -1, -6, -11, ...?
Fynjy0 [20]

Answer:

In summary, "the next three terms" are {-16, -21, -26}

Step-by-step explanation:

Note that the common difference separating the terms of 4, -1, -6, -11, ... is -5.  Each new term is found by combining the previous term with -5.

Thus, the applicable formula is a(n) = 4-5(n-1).

We should test this.  Take the term -6 and determine whether or not this formula correctly predicts the next term:  -11:

a(4) = 4-5(4-1) = 4 - 5(3) = 4 - 15 = -11 (yes).

We have the first four terms and need the 5th, 6th and 7th terms.

The fifth term, a(5), is 4-5(5-1) = 4-20 = -16

The sixth term is a(6) = 4-5(6-1) = -21

The seventh term is a(7) = 4 -5(6) = -26

In summary, "the next three terms" are {-16, -21, -26}

8 0
3 years ago
What is the probability of picking a blue marble and rolling an odd number?
Paladinen [302]

Answer:

3/6 chance.

Step-by-step explanation:

To roll an odd number on a six sided dice (Guessing it's six sided) you would have to roll either a 1, 3, or 5.  That would it 3 choices.  You get the six by taking the amount (like the amount of sides on the dice).  You would then have a 3/6 chance of rolling an odd number.

6 0
2 years ago
A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh
solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

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1 cinnamon stick equals how many teaspoons
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