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Temka [501]
3 years ago
8

Give a recursive algorithm matrix-chain-multiply(a, s, i, j) that actually performs the optimal matrix-chain multiplication for

a chain of matrices
Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0
Sorry Isk this but at least I said hi
You might be interested in
Help please?<br> Thank youu
melomori [17]
The 3rd choice is the right answer here
Hope this helps :)
Have a wonderful day !
3 0
4 years ago
one half the cost of a dress decreased by $12 is the same as 2/5 the cost of a dress. What is the cost of the dress?
guajiro [1.7K]

Answer:

$120

Step-by-step explanation:

Let the cost of the dress be "c"

ONE HALF the cost DECREASED by 12, can be written as:

\frac{1}{2}c-12

2/5th the cost of dress, can be written as:

\frac{2}{5}c

Now, we equate both parts and solve for c to get cost of dress. Shown below:

\frac{1}{2}c-12=\frac{2}{5}c\\\frac{1}{2}c-\frac{2}{5}c=12\\\frac{5-4}{10}c=12\\\frac{1}{10}c=12\\c=\frac{12}{\frac{1}{10}}\\c=12*10\\c=120

Thus,

The ccost of the dress is $120

6 0
3 years ago
In equilateral triangles STU:
Len [333]
<h3>Answer:  B) 39</h3>

==========================================================

Explanation:

Equilateral triangles have three equal sides, ie the sides are all the same length.

Let's set sides ST and TU equal to each other and solve for x

7x-10 = 2x+25

7x-2x = 25+10

5x = 35

x = 35/5

x = 7

Then we use this to compute each side

  • ST = 7x-10 = 7*7-10 = 49-10 = 39
  • TU = 2x+25 = 2*7+25 = 14+25 = 39
  • US = x^2 - 10 = 7^2 - 10 = 49-10 = 39

Each side is 39 units long, so this confirms we have the correct answer.

7 0
3 years ago
Read 2 more answers
In a box of chocolates, 1/5 of the chocolates contain nuts.
uysha [10]

Answer:

<em>1:4</em>

Step-by-step explanation:

<u>Ratios and Fractions</u>

It's given 1/5 of the chocolates in a box contain nuts. The rest do not contain nuts. The portion that does not contain nuts is:

1 - \frac{1}{5}=\frac{4}{5}

We need to calculate the ratio of the number of chocolates that contain nuts to the number of chocolates that do not contain nuts.

This can be done by dividing 1/5 by 4/5:

\displaystyle \frac{\frac{1}{5}}{\frac{4}{5}}

Operating:

\displaystyle \frac{1}{5}\cdot\frac{5}{4}=\frac{1}{4}

Expressing it as a ratio: 1:4

6 0
3 years ago
Lattice multiplication
Studentka2010 [4]
Lattice multiplication, also known as gelusia multiplication, sieve multiplication, shabakh, Venetian squares, or the Chinese lattice, is a method of multiplication that uses a lattice to multiply two multi-digit numbers.
5 0
4 years ago
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