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3 years ago

In equilateral triangles STU:

Mathematics

2 answers:

Len [333]3 years ago

7 0

<h3>Answer: B) 39</h3>

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Explanation:

Equilateral triangles have three equal sides, ie the sides are all the same length.

Let's set sides ST and TU equal to each other and solve for x

7x-10 = 2x+25

7x-2x = 25+10

5x = 35

x = 35/5

x = 7

Then we use this to compute each side

ST = 7x-10 = 7*7-10 = 49-10 = 39
TU = 2x+25 = 2*7+25 = 14+25 = 39
US = x^2 - 10 = 7^2 - 10 = 49-10 = 39

Each side is 39 units long, so this confirms we have the correct answer.

AysviL [449]3 years ago

5 0

The answer is b 39 pretty sure that’s correct

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Determine the value of x and y in the following systems of equations5x-2y=4 ; -2x+y=2.

V125BC [204]

Answer:(x,y)=(8,18)

Step-by-step explanation:

Given

5x-2y=4-------1

Second Equation

-2x+y=2-----2

Now multiply equation 2 by 2 and it to equation 1

5x-4x+0=8

x=8

substitute it in equation 1

$5\times 8-2\times y=4$

36=2y

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Therefore

(x,y)=(8,18)

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3 years ago

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3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

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3 years ago

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katrin2010 [14]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Volume = height x base x width

Volume = 4 x 4 x 4

Volume = 64

The volume is 64cm^2

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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