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3 years ago

What fraction of a cup of vegetable oil should julia use to make 1\2 of a batch of salad dressing

Mathematics

2 answers:

Archy [21]3 years ago

6 0

A. is your answer

Please mark me as brainliest. I really need it.

anastassius [24]3 years ago

5 0

A) 3/8. You cut 3/4 in half by making the bottom number twice as big and get 3/8

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Is my answer correct??

Ivanshal [37]

Answer: Last option.

Step-by-step explanation:

For this exercise it is important to remember that a Right triangle is a triangle that has an angle that measures 90 degrees.

By definition, given a Right triangle, if you draw an altitutde from the vertex of the angle that measures 90 degrees (The right angle) to the hypotenuse, the measure of that altitude is the geometric mean between the measures of the two segments of the hypotenuse.

In this case, you have the Right triangle $EFH$ given in the picture attached.

You can notice that $FG$ goes from the vertex of right angle ( $\angle F=90\°$ ) to the hypotenuse $EH$ . Therefore, it divides the hypotenuse into two segments. These are:

$EG$ and $GH$

Therefore, $FG$ is the geometric mean of the segments $EG$ and $GH$ .

6 0

3 years ago

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

Find the values of y

First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

For a saturday matinee, adult tickets cost $5.50 and kids under 12 pay only $4.00. if 60 tickets are sold for a total of $285. h

podryga [215]

30 tickets for the kids and 30 for the adult

3 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!! Simplify.

NNADVOKAT [17]

Answer: $\frac{2x(5x + 1)}{4x - 1}$

Step-by-step explanation:

$\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2}$ ÷ $\frac{2x^{2}-6x}{5x^{2}+11x + 2}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ ÷ $\frac{2x(x - 3)}{(5x + 1)(x + 2)}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ x $\frac{(5x + 1)(x + 2)}{2x(x - 3)}$

= $\frac{2x(5x + 1)}{4x - 1}$

8 0

3 years ago

What is 1+1? I really need to know. Plzzz. I'll give 58 points

Alekssandra [29.7K]

Answer: it’s 2

Step-by-step explanation:

4 0

3 years ago

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