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Viktor [21]
3 years ago
15

540=50% more than X. Find X.

Mathematics
2 answers:
NeTakaya3 years ago
8 0

Answer:

x = 270

Step-by-step explanation:

Divide 540 by 2

I hope this helps:}

Brainliest is appreciated

o-na [289]3 years ago
7 0

Answer: X = 270

Step-by-step explanation:

540 divided by 1/2? I'm pretty sure thats what ur asking right? 540 = 50% more than 270

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Find the value of x .
pantera1 [17]

Answer:

10

Step-by-step explanation:

By using intersecting chord theorem:

NH.HT=MH.HY

(x+20)*8=12*20

x+20=12*20/8

x+20=240/8

x+20=30

x=30-20

x=10

4 0
3 years ago
Two word problems :)
Likurg_2 [28]
7 out of 50 people so to find the whole amount u must multiply 50x8 to =400 and multiply 7x8 =56 therefore 56 out of 400 have traveled to a foreign country. however 56 is not MORE THAN 56. if it said 56 or more he would be correct but because he says more than 56 he is incorrect. hope that helps!
6 0
2 years ago
Pete entered a lucky draw. The probability of winning a free ticket for a soccer game is 15%. What are the ODDS AGAINST winning
svet-max [94.6K]

Answer:

3 to 20

Step-by-step explanation:

6 0
1 year ago
(no links or files) Solve this equation using the quadratic formula. This question should be solved both ways. (1) Quadratic For
meriva
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
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2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
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4 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
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