Answer:
Step-by-step explanation:
I take it that this is some sort of ratio. Start by solving the brackets on the left.
Brackets: 1/3 - 1/10
Brackets: 10/30 - 3/30
Brackets: 7/30
Brackets^2: 49/900
Brackets^2 - 1/5: 49/900 - 180/900
Brackets^2 - 1/5: -131/900
(2/5)^2 = 4/25
The way this read, it should be

Which when you invert and multiply becomes

which finally becomes

We have 20 chances out of 100 which is 20/100=1/5 other known as 1 in 5 chance
The even numbers are 2, 4, 6, .., 100. 50 chances out of 100 which is 50/100=1/2 other know as 1 in 2 chance
Answer:
x = 14
Step-by-step explanation:
comp = add up to be 90
3x + 14 + 2x + 6 = 90
5x + 20 = 90
5x = 70
x = 14
AAS Postulate
It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.
Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.
Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!
Answer:
<u>9π m²</u>
Step-by-step explanation:
We will need calculate the area of the top, the base and sides.
Area of the top=πr²
Area of the base=πr²
Area of the side: 2πrh
Surface area of a cylinder: area of the top + area of the base +area of the side
Surface area of a cylinder=πr²+πr²+2πrh=2πr²+2πrh=2πr(r+h)
Data:
r=1.5 m
h=1.5 m
Surface area of this cylinder=2π(1.5m)(1.5 m+1.5 m)=3π m*(3 m)=9π m².