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Lubov Fominskaja [6]
4 years ago
12

Why can’t web apps send notifications to a device’s taskbar when the app is closed?

Computers and Technology
1 answer:
tangare [24]4 years ago
8 0
Web apps can't send notifications when it's closed because it is not installed into the device as a software program, meaning it doesn't have enough access to do so. Plus you are closing it down so how is something that you close down supposed to work?
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Write a function shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than
Masteriza [31]

Answer:

See explaination

Explanation:

#Run the code in the python version 3.x.

#Define the function.

def shampoo_instructions(num_cycles):

#Check the cycles to be greater than 1.

if num_cycles < 1:

#Display the statement.

print('Too few.')

#Check the cycles to be greater than 4.

elif num_cycles > 4:

#Display the statement.

print('Too many.')

#The else part.

else:

#Initialize the variable.

N = 1;

#Begin the for loop.

for N in range(N, num_cycles+1):

#Print the result.

print(N , ": Lather and rinse.")

#Print the statement.

print('Done.')

#Call the function.

shampoo_instructions(2)

7 0
3 years ago
What dose a bios system do?
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If a surface is. it is exactly vertical
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3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
4 years ago
Your college has several campuses located across the city. within each campus, the buildings are interconnected with a campus ar
iris [78.8K]

Answer:

Metropolitan Area Network (MAN)

Explanation:

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2 years ago
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