1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
3 years ago
10

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

to maintain a ratio of pumpkin to green beans of 3 to 1. If he wants to use a total of 64 cans, how many cans of green beans should he use?
Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

The number of Pumpkin can used   = 48 cans

The number of Green Beans can used =   16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans =  3 :  1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of  John  wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used  = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m =  64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used  = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m =  16 cans

You might be interested in
What is the scale factor in the dilation?
Maslowich

Answer:

The scale factor in the dilation of a mathematical object determines how much larger or smaller the image will be (compared to the original object). When the absolute value of the scale factor is greater than one, an expansion occurs. When the absolute value of the scale factor is less than one, a compression occurs.

Step-by-step explanation:

4 0
3 years ago
What is a proportion in math definition ???????????????
miv72 [106K]
A proportion<span> is a name we give to a statement that two ratios are equal. It can be written in two ways: two equal fractions, or, using a colon, a:b = c:d.</span>
8 0
3 years ago
Which quadratic function has a leading coefficient of 2 and a constant term of –3?
Romashka [77]
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

<u>We are looking for a = 2, c = -3</u>

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
6 0
3 years ago
Read 2 more answers
Given the following: What is the value of x? What is the value of y? What is the m∠A? Show all work.
kondaur [170]

Answer:

angle A=angle C

angle B =angle D

to find x

x + 45 = 3x - 85 \\ x - 3x =  - 85 - 45 \\  - 2x =  - 130 \\ x = 75

to find y

x + 45 + 3x - 85 + y + y = 360 \\ 4x  + 40 + 2y = 360 \\ 4(75) + 2y = 360  - 40\\ 300 + 2y = 320 \\ 2y = 20 \\ y = 10

3 0
3 years ago
Read 2 more answers
How do I solve these trigonometric functions?
aleksandr82 [10.1K]

Answer:

see attached

Step-by-step explanation:

6 0
4 years ago
Other questions:
  • Natalia needs 9 apples to make her famous apple pie. Natalia has 25 apples. Naomi surprised her with a basket of 11 apples. How
    14·1 answer
  • Compete the square to determine minum or maxuim value of function define by -x2+10x+5
    9·1 answer
  • Given y = f(x) and y = g(x), explain the transformations from f(x) to g(x).
    6·2 answers
  • PLEASE HELP WILL GIVE BRAINLIEST!!!!!
    10·1 answer
  • Solve the formula d = rt for r.
    5·1 answer
  • Find the product (3n-4)(3n-4)
    5·2 answers
  • How many vehicles are at Nam's Gas Station?
    11·2 answers
  • I need help with this question please!!!
    13·1 answer
  • Ahhh help please find the perimeter
    9·1 answer
  • the ratio of the sides of two squares is 6:16 the area of the smaller square is 45cm2 what’s the area of the larger square
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!