The equation is 40/12=3 1/3
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
For number 3 it would be |-10| and |10|.
Number 5a is supposed to <, because -1 is greater than -7 when you look at the line graph. The same goes for 5b. 5d is >, because 0 is always greater than -1 and it shows that on the line graph that you have there. 5e is =.
I don't see anything else wrong though. Just the ones I listed.
Hope that helps!
Answer:
Your number is -10
Hope this helps :)
Step-by-step explanation:
Let x be the number
Twice a number is 2x
Added to 7 means + 7 so 2x + 7
Is means =
2x+7=
At this point I have to assume you mean
"is the same as three subtracted from THE SAME number"
Otherwise, rather than a number, we end up with the
equation of a line....
2x + 7 = x - 3 subtract x from both sides
x + 7 = -3 subtract 7 from both sides
x = -10
Your number is -10
Check: 2x+7 = x-3
2(-10) + 7 = -10-3
-20+7 = -13
-13 = -13
The answer fits the parameters of the problem.
