Slope is -2 and y-intercept is -6 how do I write the linear equation in slope intercept form
1 answer:
You might be interested in
I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
: It looks like this in the calculator
× cos A=(0.6489)
( and cos cancels out)
A=(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
(
A=
A=49.54°
check:
cos 49.54=0.6489 (its right!)
From the identity:
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)
Answer: b. g(x)=cos^-1(1/x)
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
thus,
Answer: b. g(x)=cos^-1(1/x)