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2 years ago

Pleased help please please please please.

Mathematics

1 answer:

I am Lyosha [343]2 years ago

8 0

Answer:

Step-by-step explanation:

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Kiran scored 36 baskets in 1 week. She scored 1/2 of the baskets on the weekend. She scored 1/4 of them on Tuesday, she scored 1

notka56 [123]

Answer:

6 baskets did Kiran score on Thursday

Step-by-step explanation:

As per the statement:

Kiran scored 36 baskets in 1 week.

On weekend she scored = $\frac{1}{2} \cdot 36 = 18$ baskets.

She scored 1/4 of them on Tuesday

⇒On Tuesday she scored = $\frac{1}{4} \cdot 36 = 9$ baskets

She scored 1/12 of them on Wednesday

⇒On Wednesday she scored = $\frac{1}{12} \cdot 36 = 3$ baskets.

Then;

She scored = On Weekend + On Tuesday + On Wednesday = 18+9+3 = 30 baskets.

Rest on Thursday she scored = 36 - 30 = 6 baskets.

Therefore, 6 baskets did Kiran score on Thursday

8 0

3 years ago

PLEASE HELP!!!!!!!

posledela

90° = complimentary

middle one = is neither

3rd one is supplementary

8 0

2 years ago

Jorge received a 3.1% increase in his pay at work. If he now makes $18.00 per hour, how much was he making before his raise? (Ro

g100num [7]

18 times .031 is .558
18 dollars minus .558 cents is 17.442
Answer is he was maki 17.442 dollars before the increase

6 0

2 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

Which one of the following is NOT equal to the others?

irina1246 [14]

Answer:

.03

Step-by-step explanation:

.03 would be 3% where all the others are 30% hope this helped!

5 0

3 years ago

Read 2 more answers