Question

Does anyone know the the answer to the second algebra question? Will give brainiest

Answer 1

Answer:

$\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}$

$\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}$

$x^{3} x^{\frac{1}{3} }$

Convert them, so they have a common denominator - $\frac{1}{3}$

$\frac{3}{1} * \frac{1}{3}= \frac{9}{3}$

$\frac{9}{3} + \frac{1}{3} = \frac{10}{3}$

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]