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hjlf
3 years ago
12

Does anyone know the the answer to the second algebra question? Will give brainiest

Mathematics
1 answer:
astraxan [27]3 years ago
8 0

Answer:

\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}

\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} }  = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}

x^{3} x^{\frac{1}{3} }

Convert them, so they have a common denominator - \frac{1}{3}

\frac{3}{1}  * \frac{1}{3}=  \frac{9}{3}

\frac{9}{3} + \frac{1}{3} = \frac{10}{3}

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

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