Are of the given figure is ~
The area of the compound shape is equal to ~
Area of rectangle + Area of semi - circle
let's find the Area of rectangle ~
now, let's find the Area of Semicircle ~
So, Area of the given figure is equal to ~
Answer:
y = 2x + 4
Step-by-step explanation:
First, find the <em>rate</em> <em>of change</em><em> </em>[<em>slope</em>], <em>m</em><em> </em><em>=</em><em> </em><em>-</em><em>y</em><em>₁</em><em> </em><em>+</em><em> </em><em>y</em><em>₂</em><em>\</em><em>-</em><em>x</em><em>₁</em><em> </em><em>+</em><em> </em><em>x</em><em>₂</em><em>.</em><em> </em>Next, you do either\or:
12 = 2(4) + b; 4 = b
8 = 2(2) + b; 4 = b
No matter which ordered pair you use, you will ALWAYS get the same answer, IF you put them in their correct places.
I am joyous to assist you anytime.
Answer: its x = 3
Step-by-step explanation:
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
How's anyone supposed to help you when there's no problem in your question? Use a photo or say he problem so we know what you're having trouble on. Or be a little more specific, if that's the case.
Answer:3 hours and 30 minutes
