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posledela

The probability that all 4 computers with the critical file fail in this incident

P(x=4)=0.00085

This is further explained below.

<h3>What is the probability that all 4 computers with the critical file fail in this incident? </h3>

Generally, is mathematically given as

$H \rightarrow(n, m)$

p.d.F. of Hyper Geometric distribution

given, $N=39, n=4, M=8, x=4$

$\begin{aligned}P(x=4) &=\frac{8}{4} \frac{39}{39} \\&=\frac{70 \times 1}{82251}\end{aligned}$$$

$\begin{aligned}&P(x=4)=8.5106 \times 10^{-4} \\&P(x=4)=0.00085\end{aligned}$

In conclusion, P(x=4)=0.00085

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