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lesantik [10]
3 years ago
11

(6^2)^4 ÷ 6^18 please help brainliest

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

1/60466176

Step-by-step explanation:

Given: (6^2)^4 ÷ 6^18

Parentheses: 36^4 ÷ 6^18

36^4 ÷ 36^9 (Because 6^18=6^2^9=36^9)

36^-5 (Exponents get subtracted)

1/(36^5)

1/60466176

Another way:

(6^2)^4 ÷ 6^18

6^(2*4) ÷ 6^18

6^8 ÷ 6^18

6^(8-18)

6^-10

1/(6^10)

1/60466176

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Answer:

-10

Step-by-step explanation:

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3 years ago
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"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

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From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

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6 0
2 years ago
Estimate then find the product of 758×6
Maurinko [17]
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<em>*4,200 as an estimate.</em>

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6*(758)

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dolphi86 [110]

Answer:

<em>75%</em>

Step-by-step explanation:

27 ÷ 36 = 0.75

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Hope this helped! :)

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3 years ago
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If it’s costs 60 cents for 125 grammes. How much would 100 grammes cost?
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