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DedPeter [7]
3 years ago
11

Re write tan(sin^-1(x)) as an algebraic expression

Mathematics
1 answer:
k0ka [10]3 years ago
5 0
Sketch a right triangle with base 1 and vertical leg = x. That is that angle whose tan is x. 

<span>Now compute the hypotenuse = √(x² + 1). </span>

<span>Read off the sine of the base angle (which is tan ˉ¹x) as x/√(x² + 1) </span>

<span>Done</span>
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Find The missing variable.
Vladimir79 [104]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
HURRY! Match each function with the correct inverse of the function. BEST &amp; FASTEST ANSWER GETS BRAINIEST ANSWER!!!!!!!!!
sertanlavr [38]
2 1 3 6 5 hope I helped
4 0
3 years ago
At the park there is a pool shaped like a circle. A ring-shaped path goes around the pool. Its inner diameter is 22yd and its ou
jeka94
First, we need to think about what we're actually solving for: the area of the path. To find this, we can find the area of the whole thing, minus the area of the pool.

The diagram would look something like the picture I attached. We know that to find the area of a circle, you do πr^2. The radius is half of the diameter, so halve the diameters:

22/2 = 11 yards
32/2 = 16 yards

Then solve for the area of both circles.
π11^{2}= 121π ≈ <span>380.13 (area of the pool)</span>
π16^{2}= 256π ≈ <span>804.25 (area of the whole thing)
</span>
Next, subtract the area of the pool from the area of the whole thing to find the area of the walkway:
804.25 - 380.13 = 424.12 (area of the walkway)

Finally, divide the area of the walkway by 6 to see how many gallons of paint you'll need:

424.12 ÷ 6 ≈ 70.69

So you'll need 71 gallons of paint!

Hope I helped and let me know if you have any questions :)


6 0
4 years ago
Need help with my problem of the day it’s confusing I’m not good at math :| HELP
alex41 [277]

Answer:

7:36

Step-by-step explanation:


4 0
3 years ago
Help urgent, which functions are bounded below but not above? Choose all answers that apply.
evablogger [386]

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

b. is unbounded both above and below

c. is bounded below at y = 0 and unbounded above

d. is unbounded both above and below

e. is bounded below at y = 0 and unbounded above

f. is bounded below at y = 0 and unbounded above

g. is bounded below at y = 0 and bounded above at y = 1

h. is unbounded both above and below

i. is bounded below at y = 0 and unbounded above

j. is unbounded both above and below

3 0
3 years ago
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