Answer:
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The relevant formula that we can use in this situation is:
v = v0 + at
where v is the final velocity, v0 is the initial velocity
= 20 km/hr, a is acceleration at 3.4 m/s^2 and t is time at 20 seconds
First convert v0 to m/s, v0 = 5.56 m/s
v = 5.56 m/s + 3.4 m/s^2 * 20 s
v = 73.56 m/s
Then convert back to km/hr:
<span>v = 264.82 km/hr</span>
Given t = time and h = height
From the equation.
h is the axis od symmetry
(h, k) is the vertex.
In the equation, h is 1 and k is 16.
So the maximum value is 16 at t = 1.
The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.
Answer:
c = -6
d = 2
Step-by-step explanation:
After reflection about the x-axis:
A --> A'
(x,y) --> (x,-y)
(2,3) --> (2,-3)
(4,3) --> (4,-3)
(2,6) --> (2,-6)
After translation:
(2 + c, -6 + d) --> (-4, -4)
2+c = -4
c = -6
-6+d = -4
d = 2
The range is the output or the y values in the case of this function. The only y value on this function is 1 therefore the range is 1
