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Usimov [2.4K]
3 years ago
15

Which of the following completes the proof? Triangles ABC and EDC are formed from segments BD and AC, in which point C is betwee

n points B and D and point E is between points A and C. Given: Segment AC is perpendicular to segment BD Prove: ΔACB ~ ΔECD Reflect ΔECD over segment AC. This establishes that ________. Then, ________. This establishes that ∠E'D'C' ≅ ∠ABC. Therefore, ΔACB ~ ΔECD by the AA similarity postulate. ∠ABC ≅ ∠E'D'C'; translate point E' to point A ∠ACB ≅ ∠E'C'D'; translate point E' to point B ∠ACB ≅ ∠E'C'D'; translate point D' to point B ∠ABC ≅ ∠E'D'C'; translate point D' to point A
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

∠ACB ≅ ∠E'C'D'. translate point E' to point A

Step-by-step explanation:

kotykmax [81]3 years ago
3 0

Answer: ∠ACB ≅ ∠E'C'D'; translate point D' to point B

Step-by-step explanation:

That is just my best guess.

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HELP PLEASE!
Archy [21]

Answer:

Option 2  50 ≤ s ≤ 100

Option 5 She could deposit $50

Option 6 She could deposit $75

Step-by-step explanation:

Let

s -----> amount of money Layla deposit into a saving account

we know that

25%=25/100=0.25

50%=50/100=0.50

so

s\geq 0.25*200 -----> s\geq \$50

s\leq 0.50*200 -----> s\leq \$100

The compound inequality is

\$50 \leq s\leq \$100

<em>Verify each case</em>

case 1) 25 ≤ s ≤ 50

The statement is false

see the procedure

case 2) 50 ≤ s ≤ 100

<u>The statement is True</u>

see the procedure

case 3) s ≤ 25 or s ≥ 50

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 4) s ≤ 50 or s ≥ 100

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 5) She could deposit $50

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

case 6) She could deposit $75

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

3 0
3 years ago
Read 2 more answers
Solve x^2 - x - 5/2 = 0 using the quadratic formula.
Soloha48 [4]
Using the quadratic formula, we have:

\frac{1+- \sqrt{11} }{2}, so our solutions are \frac{1+ \sqrt{11} }{2} and \frac{1- \sqrt{11} }{2}.
5 0
3 years ago
Draw the model to show 5.5/5
babunello [35]
This would be easy if you made more sense out of the question.
4 0
2 years ago
What's 5 + (7 x 8) divided by 3
Ganezh [65]

Answer:

23.6666666667

Step-by-step explanation:

6 0
3 years ago
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A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 y
kramer
Let's call the younger student's age A and the older student's age B. The teacher's age will be T.

B = 2A
T = 5B
T+5 = 5(A+5)

Simplify the last equation.

T+5 = 5A+25
T = 5A+20

Now we have two equations solved for T, so we can set them equal to each other.

5B = 5A + 20

We can plug 2A in for B

5(2A) = 5A + 20

10A = 5A + 20

5A = 20

A = 4

To find T, we plug 4 in for A in T = 5A + 20

T = 5(4) + 20

T = 40

The answer is 40 years old.


6 0
3 years ago
Read 2 more answers
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