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Usimov [2.4K]
3 years ago
15

Which of the following completes the proof? Triangles ABC and EDC are formed from segments BD and AC, in which point C is betwee

n points B and D and point E is between points A and C. Given: Segment AC is perpendicular to segment BD Prove: ΔACB ~ ΔECD Reflect ΔECD over segment AC. This establishes that ________. Then, ________. This establishes that ∠E'D'C' ≅ ∠ABC. Therefore, ΔACB ~ ΔECD by the AA similarity postulate. ∠ABC ≅ ∠E'D'C'; translate point E' to point A ∠ACB ≅ ∠E'C'D'; translate point E' to point B ∠ACB ≅ ∠E'C'D'; translate point D' to point B ∠ABC ≅ ∠E'D'C'; translate point D' to point A
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

∠ACB ≅ ∠E'C'D'. translate point E' to point A

Step-by-step explanation:

kotykmax [81]3 years ago
3 0

Answer: ∠ACB ≅ ∠E'C'D'; translate point D' to point B

Step-by-step explanation:

That is just my best guess.

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