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3 years ago

What is the remainder of the following division problem? A) x B) 1 C) 0 D) -1

Mathematics

2 answers:

Mashutka [201]3 years ago

8 0

Answer:B

Step-by-step explanation:

Diano4ka-milaya [45]3 years ago

3 0

0+1= 1 so x/1 = x don’t know about the top though

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To solve for the missing length, which operation should you perform?

Radda [10]

Answer:

? = 15 yards

Step-by-step explanation:

h² + b² = ?²

9² + 12² = ?²

81 + 144

225

√225 = 15

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3 years ago

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Phi 103 week 5 quiz up to 80% of doctors endorse this project uses which rhetorical device

Helga [31]

Up to 80% of doctors endorse this project uses Weasel Words.

Weasel Words are the statements that are intentionally ambiguous or misleading.
These words are commonly used in advertising and in political statements to mislead.

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4 years ago

Heyyy ummm... help??

atroni [7]

The statements true for the given function are:

$f(0) = \frac{3}{2}$
$f(4) = \frac{7}{2}$

I tried them all and these two were correct, their solutions are as follows:

= f(x) = 1/2x + 3/2

= f(0) = 1/2 × 0 + 3/2

= f(0) = 0 + 3/2

= f(0) = 3/2

= f(x) = 1/2x + 3/2

= f(4) = 1/2 × 4 + 3/2

= f(4) = 2 + 3/2

= f(4) = 4+3/2

= f(4) = 7/2

So, that's how these two are correct.

7 0

3 years ago

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

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What is the value of this expression? (-2)^5

s344n2d4d5 [400]

(-2)⁵................ => (-2)(-2)(-2)(-2)(-2)...........=> -32.

recall, minus times minus is plus, and minus times plus is minus.

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3 years ago

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