SO,
1 answer:
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Answer:
<em>y = - 0.5 | x - 5 | + 2</em><em> </em>
Step-by-step explanation:
g(x) = |x|
step - shifts right 5 units: g(x + 5) = | x <u><em>- 5</em></u> |
step - shifts up 2 units: g(x + 5) + 2 = | x - 5 | <u><em>+ 2</em></u>
step - reflected: - g(x + 5) + 2 =<em> - </em>| x - 5 | + 2
step - stretched by 0.5: <em>y = - </em><u><em>0.5</em></u><em> | x - 5 | + 2</em>
<em>y = - 0.5 | x - 5 | + 2</em>
Answer:
a. The time to strike the ground is 5 seconds
b. The time for the ball to be over than 96 ft is 1 second
Step-by-step explanation:
a. When the ball thrown vertically up ward to reach its maximum height at velocity = 0 then complete its motion vertically down ward to strike the ground its displacement = zero
∴ s(t) = 0 ⇒
∴
5 - t = 0⇒ ∴ t = 5 seconds
b. To tind the time that the ball will be over 96 ft over the ground substitute in
t = 3 sec. and t = 2 sec.
The ball will be at height 96 ft at time 2 sec. and 3 sec.
So the ball will be at height over than 96 = 3 - 2 = 1 sec.