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gladu [14]
3 years ago
8

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure.

Mathematics
1 answer:
kow [346]3 years ago
8 0

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{3\sqrt{2}}\\ b=\stackrel{opposite}{3\sqrt{2}}\\ \end{cases} \\\\\\ c=\sqrt{(3\sqrt{2})^2+(3\sqrt{2})^2}\implies c=\sqrt{3^2\sqrt{2^2}+3^2\sqrt{2^2}}\implies c=\sqrt{18+18} \\\\\\ c=\sqrt{36}\implies c=6

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fgiga [73]
For this case we have the following table:
 X    F(x) 
 -1   -11 
 0    -1 
 1     9
 From here, we look for the function f (x).
 We then have that as the equation is linear:
y-yo = m (x-xo)

 Where,
 m = (y2-y1) / (x2-x1)


 m = (9 - (- 1)) / (1-0)

 m = (9+1)/(1)

m = 10
 We choose an ordered pair:
 (xo, yo) = (0, -1)

 Substituting values:
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 Rewriting:
 y = 10x - 1

 Thus, the function f (x) is:
 f (x) = 10x - 1

 On the other hand, the function g (x) is:
 g (x) = 5x +1

 Answer:
 
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The intersection with the y axis of g (x) is greater than the intersection with the y axis of f (x) (1> -1)
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3 years ago
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