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gladu [14]
3 years ago
8

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure.

Mathematics
1 answer:
kow [346]3 years ago
8 0

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{3\sqrt{2}}\\ b=\stackrel{opposite}{3\sqrt{2}}\\ \end{cases} \\\\\\ c=\sqrt{(3\sqrt{2})^2+(3\sqrt{2})^2}\implies c=\sqrt{3^2\sqrt{2^2}+3^2\sqrt{2^2}}\implies c=\sqrt{18+18} \\\\\\ c=\sqrt{36}\implies c=6

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<span><u><em>Answer:</em></u>
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<u><em>Explanation:</em></u>
<u><em>Let's take a look at each one of them separately:</em></u>
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The fraction is formed by dividing one part over five

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</span>\frac{5}{1}<span> : This fraction is not in the simplest form. We can divide 5 by 1 and the answer would be 5. Therefore, </span>\frac{5}{1}<span> is equivalent to 5.

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