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gladu [14]
3 years ago
8

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure.

Mathematics
1 answer:
kow [346]3 years ago
8 0

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{3\sqrt{2}}\\ b=\stackrel{opposite}{3\sqrt{2}}\\ \end{cases} \\\\\\ c=\sqrt{(3\sqrt{2})^2+(3\sqrt{2})^2}\implies c=\sqrt{3^2\sqrt{2^2}+3^2\sqrt{2^2}}\implies c=\sqrt{18+18} \\\\\\ c=\sqrt{36}\implies c=6

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Step-by-step explanation:

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We convert the given information to equations, step by step.

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So,

y = 1 + x

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4 0
2 years ago
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6.68, 13.37, 14.95

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b = 2a

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c² = a² + b²

Three equations, three variables.  Start by plugging the first equation into the second and solving for c.

35 = a + 2a + c

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2 years ago
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Answer:

50:3

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3 years ago
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