It is b because the answer is a trick to every one they make you think it’s c but it’s really b. That’s the answer b
Answer:
true, false, true, true
Step-by-step explanation:
The set names in this diagram have nothing to do with exponents, radicals, and polynomials. We'll take the diagram at face value.
(a) The labels on the sets seem to be appropriately placed.
__
(b) "Some" in this context means "any or all of the set". Since all of the circle representing integers is outside the rectangle representing irrational numbers, it is TRUE that some integer are not irrational numbers.
No part of the circle representing whole numbers is inside the rectangle representing irrational numbers, so it is FALSE that some whole numbers are irrational numbers.
A portion of the circle representing integers is outside the circle representing whole numbers, so it is TRUE that some integers are not whole numbers.
Every part of the circle representing whole numbers is inside the rectangle representing rational numbers, so it is TRUE that all whole numbers are rational numbers.
Answer:
4
Step-by-step explanation:
Given:
A, B, C, D have distinct positive values for mod 6
A (mod 6) = 1
B (mod 6) = 2
C (mod 6) = 4
D (mod 6) = 5
Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.
Furthermore, in order that ABCD mod 6 > 0, we cannot have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.
Thus the only positive residues can only be 1,2,4,5
A*B*C*D (mod 6) > 0 = 1*2*4*5 (mod 6) = 4
Answer:
2550
Step-by-step explanation:
Answer:
16k-10k
Step-by-step explanation:
This is the same equation just before its simplified.
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