Need help with this (Venn Diagram with with Exponents, Radicals, and Polynomials)
1 answer:
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Based on the construction, we can logically deduce that: A. yes; the compass was kept at the same width to create the arcs for points C and D.
<h3>What is a line segment?</h3>A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.
In Geometry, a line segment can be measured by using the following measuring instruments:
- A scale (ruler)
- A divider
- A compass
In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.
Based on the construction with arcs created above and below the line segment from points A, we can infer and logically deduce that it is true that the compass was kept at the same width to create the arcs for points C and D.
In conclusion, yes, the construction demonstrated how to bisect a line segment correctly by hand.
Read more on arcs here: brainly.com/question/11126174
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Complete Question:
The construction has a given segment AB. Arcs have been created above and below the segment from points A that are equidistant from point A. The compass was kept at the same distance, placed on point B, and two additional arcs were created above and below the segment that intersect with the first arcs created. The intersection of the arcs above the segment created point C. The intersection of the arcs below the segment created point D. A line was drawn from point C to D through the segment.
Does the construction demonstrate how to bisect a segment correctly by hand?
A. Yes; the compass was kept at the same width to create the arcs for points C and D.
B. Yes; a straightedge was used to create segment CD.
C. No; the compass was not kept at the same width to create the arcs for points C and D.
D. No; a straightedge was used to create segment CD.
Answer: option c
Step-by-step explanation:
Find the x-intercept and y-intercept of each line.
To find the x-intercept, substitute into the equation and solve for "x".
To find the y-intercept, substitute into the equation and solve for "y".
- For the first equation:
x-intercept
y-intercept
Graph a line that passes through the points (7.25, 0) and (0, 9.66)
- For the second equation:
x-intercept
y-intercept
Graph a line that passes through the points (0.5, 0) and (0, -0.33)
Observe the graph attached. You can see that point of intersection of the lines is (5,3); then this is the solution of the system. Therefore:
