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vesna_86 [32]
3 years ago
8

24% of 289 estimate using a rate per 100

Mathematics
1 answer:
tangare [24]3 years ago
7 0
The answer to 24% of 289 is 69.36
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um 6/1?

Step-by-step explanation:

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B.

Step-by-step explanation:

When written as proportions, the ratios of oranges to cups of juice are always equal.

8 0
4 years ago
A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample
leva [86]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.25 represent the population standard deviation

n represent the sample size (variable of interest)  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

8 0
4 years ago
Find f(-2) for f(x)=2*3^x
vlabodo [156]
Replace x with -2

2 * 1/9= 2/9
8 0
3 years ago
Please help me with thissss
Evgesh-ka [11]

Answer:

a.) The sum of the weights of the two in insects is 0.0031 grams. (0.0031 grams)

b.) The fly is 0.0013 grams heavier than the gnat. (0.0013 grams)

Step-by-step explanation:

2.2 * 10^-3 = 2.2 * 1/1000 which is 2.2/1000.

9 * 10^-4 = 9 * 1/10000 = 9/10000

To add 9/10000 to 2.2/1000 we have to find the common denominator, which will be 10000.

So we do:

2.2/1000 * 10/10 = 22/10000

9/10000 + 22/10000 = 31/10000 = 0.0031.

The sum of the weights of the two in insects is 0.0031 grams.

To find how much heavier the fly is than the gnat we do:

22/10000 - 9/10000 = 13/10000 = 0.0013

The fly is 0.0013 grams heavier than the gnat.

7 0
3 years ago
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