Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Answer:
x=1/13 y=15/26
Step-by-step explanation:
hope this helps!
please mark me brainliest! thanks!
Answer:
5x+8y
Step-by-step explanation:
We can first open the brackets by using the distrubitive propety.
2(x+4y)+3x
2x+8y+3x
Now we can combine like terms.
5x+8y.
I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.
Hoped this helped,
JoeLouis2
Answer:
12x + 15y=34
x=34/12 = 17/6
y=34/15
____________________
-6x + 5y=3
x=3/-6 = 1/-2
y= 3/5
Step-by-step explanation: