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Vaselesa [24]
3 years ago
11

30 PTS BRAINLIEST FOR BEST ANSWER The graph of f(x) = (0.5)^x is replaced by the graph of g(x) = (0.5)^x − k. If g(x) is obtaine

d by shifting f(x) down by 2 units, the value of k is ________.
Mathematics
1 answer:
pogonyaev3 years ago
5 0
The graph of f(x) = (0.5)^x is replaced by the graph of g(x) = (0.5)^x − k. If g(x) is obtained by shifting f(x) down by 2 units, the value of k is 2 because g(x)=(.5)x-2. g(x) is f(x) without the "shift" and it said the shift was 2 units, so k is 2
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olchik [2.2K]

Answer:

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Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

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What does rotation summery means in your own words?
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Solve 3y - 15 = y+1 with steps shown
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Answer:

y = 8

Step-by-step explanation:

Hello!

We can solve for y by isolating it.

<h3>Solve for y</h3>
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  • 3y - 15 - y = y +1 - y
  • 2y - 15 = 1
  • 2y - 15 + 15 = 1 + 15
  • 2y = 16
  • y = 16/2
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The value of y is 8.

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2 years ago
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Convert 35 mi/h to km/h
notsponge [240]
<span>Convert 35 mi/h to km/h

</span>35  \dfrac{mi}{h}\to  \dfrac{km}{h}\qquad \qquad 1 mi= 1,60934 \\  \\  \\ 35  \dfrac{mi}{h}* \dfrac{1,60934\ km}{1\ mi}= \boxed{  56,3269\dfrac{km}{h} }<span>
</span>
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