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sineoko [7]
3 years ago
9

Please help please please help

Mathematics
2 answers:
Lana71 [14]3 years ago
6 0

Answer:

The correct answer is B. 3 ft, 6 ft, 5 ft

Step-by-step explanation:

A right triangle has side lengths that equal 90 degrees

3 x 6 x 5 = 90 ft.

cestrela7 [59]3 years ago
4 0

Answer:

It should be B

I hope i helped!

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Use calculations and words to show<br>this quadrilateral meets the<br>definition of a kite.❤​
Y_Kistochka [10]

Answer:

Step-by-step explanation:

A kite is a quadrilateral that has only one line of symmetry, and bisecting diagonals.

From the graph,

AB = 6 units

BC = 8 units

CD = 8 units

AD = 6 units

i. Has exactly one pair of congruent sides. Examples are; AB = AD and BC = CD.

ii. The diagonals are perpendicular. AC is at right angle to DB.

iii. The diagonals bisect each other. AC bisects DB, or vice versa.

Therefore, quadrilateral ABCD is a kite.

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Nutka1998 [239]
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3 years ago
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podryga [215]

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5 0
3 years ago
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
Vesnalui [34]

Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

(c) 0.0401

(d) 0.6464

Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0
3 years ago
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