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Sav [38]
3 years ago
13

Who speak spanish? Oh and also solve this =

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0
The answer to your question is 95,460
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A statistics instructor likes to assign the material as reading in the textbook and then give a pretest before covering the mate
klio [65]

Answer:

b. The student's scores on the posttest would have a smaller standard deviation.

Step-by-step explanation:

The first test is taken before the material is covered in class so we expect the standard deviation to be high because not everyone's scores would be lying close to the mean. Equal number of students mastered most, some or almost none of the material from reading the textbook based on the pretest result. this means the data is varying, so the standard deviation is large.

Whereas, after the teacher has taught the material and given the homework, they must have understood most of the material. The test they take after teaching as a post test. The results of the post test would have a smaller standard deviation as most of the students would have scored good. Hence, the student's scores on the posttest would have a smaller standard deviation.

8 0
3 years ago
What does x equal and how do I find x?
Oduvanchick [21]
If angles are the same, then their opposite edges also the same. So 2x-6 = x

If you solve it you will find x=6
3 0
3 years ago
Read 2 more answers
How much larger would the volume of a prism be if it was increased by a scale factor of 5
jek_recluse [69]
We know that

if  the volume of a prism <span>it was increased by a scale factor of 5
then
</span>the original volume is multiplied by 5*5*5-------> 5³=125

therefore 
the new volume compared with the original is 125 times larger 
7 0
3 years ago
What is the factored form of 6n4 – 24n3 + 18n?
seropon [69]

Answer: Its factored form will be

6n(n-1)(n^2-3n-3)

Step-by-step explanation:

Since we have given that

6n^4-24n^3+18n

So, we need to factor ,

6n(n^3-4n^2+3)

Now,

\text{Let }p(n)=n^3-4n^2+3

Now, by hit and trial method, we put n=1,

p(1)=1^3-4\times1^2+3=1-4+3=1-1=0

n=1\\n-1=0

So, n-1 is also factor of p(n).

Now,

\frac{n^3-4n^2+3}{n-1}=n^2-3n-3

So, its factored form will be

6n(n-1)(n^2-3n-3)

8 0
3 years ago
Read 2 more answers
Help me out plzz and I'll do the same
elixir [45]
I think it's -2 to -1 is the right answer maybe

but i hope it helps u !!
6 0
2 years ago
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