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3 years ago

What is the answer to 2-(y+2)=3y

Mathematics

2 answers:

Lynna [10]3 years ago

7 0

Answer: y=0

Step-by-step explanation: first you distribute

then you add y on both sided

then you combind like terms then divide by 4

Vinil7 [7]3 years ago

6 0

If you multiply 2 with Y and 2 you would get 2y+4=3y and then you would need to subtract 2y from both sides and you will end up wit Y=4

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Assuming the population of interest is approximately normally distributed, construct a 95% confidence interval estimate for th

nikklg [1K]

Answer: $(17.96,20.64)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\ \pm\ t_{n-1,\alpha/2}\dfrac{s}{\sqrt{n}}$

Given : $\overline{x}=19.3$

$s= 3.1$

n=23, which is a small sample(n<30), so we use t-test.

Significance level: $1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{22,0.025}=2.074$

Then , the confidence interval for population mean will be :-

$19.3\ \pm\ (2.074)\dfrac{3.1}{\sqrt{23}}\\\\\approx19.3\pm1.34\\\\=(19.3-1.34,19.3+1.34)\\\\=(17.96,20.64)$

Hence, the 95% confidence interval for the population mean is $(17.96,20.64)$

4 0

3 years ago

Learn with an example

malfutka [58]

Answer:

200

Step-by-step explanation:

1. 4 times 5 because there are 5 types in total and they make 4 of each type in each batch they bake. 4*5 is 20.

2. 20 times 10 because they make 10 batches and you know there are 20 in each batch. so 20 times 10 is 200.

200 is the answer.

4 0

3 years ago

Write the slope-intercept form of the equation of each line

Vera_Pavlovna [14]

First let's talk about the blue line.

You can see its rising so its slope is certainly positive. But by how much is it rising? You can observe that each unit it rises it goes 1 forward and 1 up so its slope is the ratio of 1 up and 1 forward which is just 1.

We have thusly,

$y=x+n$

Now look at where blue line intercepts y-axis, -1. That is our n.

So the blue line has the equation of,

$y=x-1$

Next the black lines. The black lines are axes so their equations are a bit different.

First let's deal with x-axis, does it have slope? Yes but it is 0. The x-axis is still, not rising nor falling. Where does x-axis intercept y-axis? At 0. So the equation would be,

$y=0x+0=0$

Now we have y-axis. Does y axis have a slope? Yes but it is $\infty$ . The y-axis rises infinitely in no run. Where does it intercept y-axis? Everywhere! So what should the equation be? What if we ask where does y-axis intercept x-axis and write its equation in terms of x. Y-axis intercepts x-axis at 0 which means its equation is,