6,000 is the value of 6 in 106,534
Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
first answer:-1.75
second:-15.75
third:-40.25
Step-by-step explanation:i am too lazy srry
4.57 rounded to the nearest whole number is 5
