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4 years ago

What is the area of a equilateral triangle with a height of 7 yards?

Mathematics

1 answer:

Andrej [43]4 years ago

3 0

Approximately 21.22 yards.

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The price of a car increased by 7% which expression can be used to calculate the new price of the car

julsineya [31]

Answer: P * ( 1 + 7%)

Step-by-step explanation:

You included no options but the expression should go something like this:

Pn = P * ( 1 + 7%)

Where Pn is the new price

P is the current price

<em>The above formula will show the new price given the current price. </em>

6 0

3 years ago

I need help with this math

enot [183]

Answer:

question? haven't learn this yet but try asking desmos that app helps me a lot!

3 0

3 years ago

What is [b-5] over 8=5

julia-pushkina [17]

Answer:

B=45

Step-by-step explanation:

Multiply 8 by 5

Add 40 and 5 together

6 0

3 years ago

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

3 years ago

Find the equation of the tangent to the circle x2 + y2 = 109 at point (-10,3)

konstantin123 [22]

Answer:

10x - 3y = -109 .

Step-by-step explanation:

x^2 + y^2 = 109

Implicit Differentiation:

2x + 2y.y' = 0

y' = -2x/2y = -x/y

So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.

Equation of the tangent:

y - y1 = m(x - x1)

y - 3 = 10/3(x + 10)

y - 3 = 10/3 x + 100/3

3y - 9 = 10x + 100

-109 + 3y = 10x

10x - 3y = -109

4 0

3 years ago