X^4 - 5x^2 - 36 = 0
(x^2 - 9)(x^2 + 4) = 0 - factor the left side
(x + 3)(x - 3)(x^2 + 4) = 0 - factor (x^2 - 9 as difference of squares)
x + 3 = 0 x - 3 = 0 x^2 + 4 = 0 Set each factor to 0 if any 0 the left side 0
x = -3 x = 3 x^2 = -4
x = 2i or -2i
The roots are 3, -3, 2i, -2i (Don't know if you need the imaginary roots but I gave you them anyway)
There you go :) hope this helps!
Hope this helped! I’d appreciate brainless answer!
Answer:
![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
Step-by-step explanation:
Given :
QR⊥PT
![\angle QPR = \angle STR](https://tex.z-dn.net/?f=%5Cangle%20QPR%20%3D%20%5Cangle%20STR)
To Prove : ![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
Solution:
Statements Reasons
QR⊥PT Given
∠QRP and ∠SRT are right angles Def of perpendicular
∠QPR≅∠STR Given
∠QRP = ∠SRT All right angles are equal
ΔPQR≈ΔTSR AA similarity
Hence ![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
A and B
8/16 = 1/2
A=1/2
B=2/3
C=1/2
D=1