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2 years ago

Please help me, I don’t know how to solve for x on this one

Mathematics

1 answer:

Brums [2.3K]2 years ago

5 0

Use trigonometry to solve for x.

The tangent function is defined to be opposite side divided by the adjacent side.

tan(78) = x/10

tan(78)(10) = x

47.0463010948 = x

We now round off to two decimal places. In other words, we round off to the nearest tenths.

47.05 = x

Done!

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Help. Me. Please. Pt1

sergejj [24]

Answer:

Step-by-step explanation:

X<Y means x is less than y-5 and you get A.

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2 years ago

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What is the answer for -104 = 8x

meriva

Okay, all we need to do is divide 8 from both sides:

-104/8=-13

So x=-13
:D

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2 years ago

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Find the length of the following curve. If you have a grapher, you may want to graph the curve to see what it looks like.

stepladder [879]

The length of the curve $y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

$y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6

Start by differentiating the curve function

$y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x$

Evaluate

$y' = x(9x^2 + 6)^\frac 12$

The length of the curve is calculated using:

$L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx$

This gives

$L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx$

Expand

$L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx$

This gives

$L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx$

Express as a perfect square

$L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx$

Evaluate the exponent

$L =\int\limits^6_3 {3x^2 + 1} \ dx$

Differentiate

$L = x^3 + x|\limits^6_3$

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

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7 0

1 year ago

NEED ANSWERED ASAP please find the volume of the cone and cylinder.

Mkey [24]

Cone volume= 285 ( the radius would be 5.5)
Cylinder volume =95 same radius as well

4 0

2 years ago

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Given the center (h,k) = (5,0) and radius r=3, write and equation for the circle in standard form

Len [333]

Answer

B) $(x-5)^{2} + y^{2} = 9$

Step by step explanation

The standard form of circle when center(h, k) and radius r, given is

(x - h)^2 + (y - k)^2 = r^2

Given: (h, k) = (5, 0) and r = 3

Now plug in these values in the standard form, we get

(x - 5)^2 + (y - 0)^2 = 3^2

$(x- 5)^{2} + y^{2} = 9$

Therefore, the answer is B) $(x-5)^{2} + y^{2} = 9$

Thank you :)

3 0

2 years ago

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