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Darya [45]
3 years ago
9

Find all complex solutions of 3x^2+3x+7=0

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer: this would be ur answer 100%

Step-by-step explanation:

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4 years ago
Will Mark Brainlest help please​
spayn [35]

Answer:

g(-1 )=-1 and g(2)+g(1)=7

Step-by-step explanation:

If g(x) = x^3+x^2-x-2 find g(-1)

if we find g(-1)

we substitute all the x's in the function with -1

-1^3+-1^2-(-1)-2

-1^3 = -1

-1^2 = 1

-1+1+1-2

(two minuses make a plus)

-1+1 = 0

0+1 = 1

1-2 = -1

if x=-1, g(-1) is -1

g(2)+g(1)

substitute the x's in the function with 2 and 1 and add your results

2^3+2^2-2-2

2^3 = 8, 2^2 = 4

8+4-2-2

8+4= 12, 12-2 = 10, 10-2 = 8

g(2)=8

g(1) now

1^3 + 1^2-1-2

1^3=1, 1^2 = 1

1+1-1-2

1+1 = 2, 2-1 = 1, 1-2 = -1

g(3) = -1

g(2) (which equals 8) + g(3) (which equals -1) =

8+(-1) = 7

g(2)+g(3)=7

5 0
3 years ago
Use pemdas (18 - 14) x (4 x 2) write 3 steps
Deffense [45]

Answer:

32

Step-by-step explanation:

Parentheses:

(18 - 14) = 4

(4 x 2) = 8

4 x 8

Multiplication:

4 x 8 = 32

<em>good luck hope this helps :)</em>

7 0
3 years ago
Read 2 more answers
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