Answer:
Step-by-step explanation:
move the decimal so there is one non-zero digit to the left of the decimal point. the number of decimal places you move will be the exponent on the 10. if the decimal is being moved to the right, the exponent will be negative. if the decimal is being moved to the left, the exponent will be positive.
The answer would be to the right since after you factor the equation out the 9 is positive
We start with
and wish to write it as
First, pull 2 out from the first two terms:
Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have
and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square:
The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have
and when we multiply that out it does not give us what we started with. It gives us
So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.
We do this as follows:
which gives us the final expression we seek:
If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e = -103
We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106
Answer:
Step-by-step explanation:
In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula
prt = I, where
p is the initial investement,
r is the interest rate in decimal form,
t is the time in years, and
I is the interest earned. Notice that we have all those things but the p.
Filling in:
p(.0425)(4) = 2380 and
.17p = 2380 so
p = 14000
That means that 14000 was initially invested. If the depositor withdrew the 2380, then
14000 - 2380 is the amount left in the account, namely, $11620
Answer:
○B. 
Step-by-step explanation:
Trigonometric Identities
<u>Radius Formula</u>
![{[-\sqrt{15}]}^{2} + {[-\sqrt{10}]}^{2} = {r}^{2} → 15 + 10 = {r}^{2} → 25 = {r}^{2}\\ \\ 5 = r](https://tex.z-dn.net/?f=%7B%5B-%5Csqrt%7B15%7D%5D%7D%5E%7B2%7D%20%2B%20%7B%5B-%5Csqrt%7B10%7D%5D%7D%5E%7B2%7D%20%3D%20%7Br%7D%5E%7B2%7D%20%E2%86%92%2015%20%2B%2010%20%3D%20%7Br%7D%5E%7B2%7D%20%E2%86%92%2025%20%3D%20%7Br%7D%5E%7B2%7D%5C%5C%20%5C%5C%205%20%3D%20r)
* Since we are talking about radii, we only want the NON-NEGATIVE root.
In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the <em>tangent</em><em> </em>ratio:
I am joyous to assist you anytime.
