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dedylja [7]
3 years ago
5

An object on Jupiter weighs about 2.5 times as much as the same object would weigh on Earth. If a person on Earth weighs 135 lb.

, how much does the person weigh on Jupiter? A. 54 lb. B. 137.5 lb. C. 337.5 lb. D. 3375 lb.
Mathematics
2 answers:
aleksley [76]3 years ago
7 0
The answer is C. Because 137 x 2.5=337.5 lbs. 
siniylev [52]3 years ago
4 0
That person would weigh 337.5 pounds

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Phantasy [73]

Answer:

Step-by-step explanation:

2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3})  } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}

\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)

or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )

5 0
3 years ago
Pauley graphs the change in temperature of a glass of hot tea over time. He sees that the function appears to decrease quickly a
worty [1.4K]

Answer: d

Step-by-step explanation:

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2 years ago
Can someone please help with these question
GalinKa [24]

Answer:

1) 81.64 ft      2) 12.56 in

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a radius is a line <em>halfway</em> through the circle starting in the middle... a diameter is double that, or a line that goes <em>all the way </em>through the circle

you are working with diameter

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3 years ago
Given the sequence 4, 8, 16, 32, 64, ..., find the explicit formula.
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Answer:

\sf 2^{(n+1)}

Step-by-step explanation:

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  \sf \boxed{\bf t_n=ar^{(n-1)}}

Here, a is the first term.

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2 years ago
Question 20 points if correct
Vlada [557]

Answer:

B = 155° , C = 25° , D = 155°

Step-by-step explanation:

Given

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Also

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5 0
3 years ago
Read 2 more answers
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