There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>
1- 5 ways
2- 5/16
3- 1/16
4- 1/16
In the question given above n= 5 p =1/2 q= 1/2 r is the given point.
- <u>Part 1:</u>
The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore
nCr= 5C4= 5 ways
<u>2. Part 2:</u>
The probability that all four people get off the bus on the first stop is given by :
P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16
<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16
<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16
For binomial distribution click
brainly.com/question/15246027
brainly.com/question/13542338
Answer:
Always
Step-by-step explanation:
They never intersect
Answer:
The solution is (-2/3,7/3)
Step-by-step explanation:
1) What is the bottom part saying? I will just solve what I see on top since that may be the only part you need to solve, comment what the bottom part is if you need it, I'll help.
2) y=7/3 by solving. for y.
3) x = -4/6 by solving for x after plugging in the y.
4) Your answer is (-2/3,7/3).
Answer:
#1 is 39
#2 is 10 1/2
Step-by-step explanation:
Hopefully this helped, if not HMU and I will try my best to get you a better answer!
Have a great thanksgiving break :)
