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den301095 [7]
3 years ago
8

For a given pair of points, find the equation of the line y=mx+b that goes through the points by solving a system of linear equa

tions. (3,3) and (5,7)
Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

y = 2x - 3

Step-by-step explanation:

the formula for finding equation of a line is m = (y2 - y1 )/(x2 - x1). that is (7-3)/(5-3) which gives you 4/2 = 2.

you then chose one of the point and fill in the equation y - y1 = m (x -x1)

So let's chose (3,3) and fill in.

y - 3 = 2 (x - 3)

y - 3 = 2x - 6

y - 2x = -6 + 3

y - 2x = -3

Hence, the equation of the line is y = 2x - 3

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On what date did Thomas jefferson submit the Declaration of Independence to peers for editing?
PSYCHO15rus [73]

Answer:

C. June 28, 1776

Step-by-step explanation:

Submitting the Declaration of Independence to the Continental Congress, June 28, 1776. This image is considered one of the most realistic renditions of this historical event.

7 0
4 years ago
Read 2 more answers
2(x - 3) = 4x - 1
SSSSS [86.1K]

Answer:

Hello the answer is

x= -2 1/2

3 0
3 years ago
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In rectangle QRST, QS= 3x + 7 and RT= 5x - 3. Find the lengths or the diagonals of QRST
Marina CMI [18]

Answer:

The lengths of the diagonals is 22.

Step-by-step explanation: Since the shape is a rectangle, the diagonals are congruent, we can form the equation 3x+7=5x-3.

Solve for x; 2x=10-->x=5.

Plug 5 into one of the equations. 3(5)+7=22. 5(5)-3=22

Hope this helps!

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8 0
3 years ago
Help me pls due in 5 mins​
Drupady [299]

Answer: 215\ cm^2

Step-by-step explanation:

Given

Here the given figure can be divided into two shapes i.e. rectangle and a trapezium

For rectangle ABCD Area = 10\times8=80\ cm^2

Area of trapezium CEFD Area is \frac{1}{2}[\text{sum of non-parallel sides}]\times[\text{distance between them}]

\Rightarrow \frac{1}{2}\times [10+17][10]=135\ cm^2

Total shaded area =80+135=215\ cm^2

5 0
3 years ago
The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and
timofeeve [1]

Answer:

Width = 2\frac{1}{4}cm

Length=5\frac{5}{12} cm

Step-by-step explanation:

Data from the question;

Perimeter of a rectangle is 15\frac{1}{3} cm

Length is 3\frac{1}{6} cm longer than the width

We are supposed to determine the length and the with of the rectangle;

Assuming, the width x cm

Then, the length is x+3\frac{1}{6} cm

We need to know that the perimeter of a rectangle is given by;

Perimeter = 2 ( length + width)

Therefore;

15\frac{1}{3}= 2 ( x + (x+3\frac{1}{6}))

15\frac{1}{3}=2(2x+3\frac{1}{6})

Thus;

15\frac{1}{3}=4x+6\frac{1}{3}

4x=9\\x=2\frac{1}{4}

Therefore;

Width = 2\frac{1}{4}cm

Length = x + 3\frac{1}{6}

           =2\frac{1}{4}+3\frac{1}{6}

            =5\frac{5}{12} cm

Therefore; the length is 5\frac{5}{12} cm while the width is 2\frac{1}{4} cm

7 0
3 years ago
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