In △BAH and △CAK
AB = AC (Given congruent sides of triangle)
m∠BAK = m∠CAH ( Given congruent angles)
AH = AK (Given congruent sides of triangle)
Therefore, triangle △BAH congruent to triangle △CAK.
△BAH ≅ <u>△CAK </u>by (<u>Side Angle Sngle or SAS triangle congruency postulate</u>).
Therefore, m∠K = m∠H (Congurent parts of the congruent triangles are congruent).
Answer:
Step-by-step explanation:
We can do this by cross multiplying.
14/6=x/21
=49/21
Answer:
27i
Step-by-step explanation:
Since we define <em>i</em> as 
, 
