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2 years ago

9,15,15,6,10,19,14,16 What is the Mean , Median , Mode and Range ?

Mathematics

2 answers:

lesya692 [45]2 years ago

7 0

Answer:

The mean is 104 (Just add them all up)

The median is either 6 or 10 (its the number in the middle, sometimes there are two medians)

The mode is 15 (It shows up more than once)

The range is 13 (Take the smallest number and the highest number and subtract)

mel-nik [20]2 years ago

4 0

Answer:

Total Numbers in Set:

Mean (Average):

Median (Middle):

(14+15)/2 = 14.5

Mode (Most Common):

Range (Biggest - Smallest):

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Write an equivalent expression for -(3b+2)+4

Lerok [7]

Answer:

-3b+2

Step-by-step explanation:

-3b-2+4

-3b+2

4 0

3 years ago

In rectangle ABCD, if the coordinates of A are (0, 0) and of C are (r, s), find the coordinates of B and D.

goldenfox [79]

Answer:

Answers are (r,0) and (0,s)

Step-by-step explanation:

Given that in a rectangle ABCD, one vertex is the origin (0,0) A

The opposite vertex C is having coordinates as (r,s)

Since a rectangle has angle 90 we have x axis as one side and y axis as other side.

Length = r and width =s (since coordinates of C are (r,s))

Hence other coordinate B on x axis would be = (r,0)

and D on y axis = (0,s)

Answers are (r,0) and (0,s)

3 0

2 years ago

Read 2 more answers

Find the third order maclaurin polynomial. Use it to estimate the value of sqrt1.3

vodka [1.7K]

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

<h3>Find the third order maclaurin polynomial:</h3>

Given the polynomial,

$f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }$

The formula to find the maclaurin polynomial,

$f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

Next we have to find f'(x), f''(x) and f'''(x),

$f'(x) = \frac{3}{2}(1+3x)^{-\frac{1}{2} }$

$f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }$

$f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }$

By putting x = 0 , we get,

$f(0)=(1+3(0))^{\frac{1}{2} }=1$

$f'(0) = \frac{3}{2}(1+3(0))^{-\frac{1}{2} }=\frac{3}{2}$

$f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}$

$f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}$

Therefore the maclaurin polynomial by using the formula will be,

$\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$

To find the value of $\sqrt{1.3}$ we can use the maclaurin polynomial,

$\sqrt{1.3}$ is $\sqrt{1+3x}$ with x = 1/10,

$\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}$

$\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14$

Hence $\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14.

Learn more about maclaurin polynomial here:

brainly.com/question/24188694

#SPJ1

6 0

1 year ago

Read 2 more answers

Plz help <br> By today evening

PIT_PIT [208]

Answer:

Wednesday night game

Step-by-step explanation:

-9 is less than -3

3 0

3 years ago

A. A 5in radius ball is in a

abruzzese [7]

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

$V_{ball} = \frac{4}{3} \pi r^3$

$V_{ball} = \frac{4}{3} \times 3.14(5)^3$

$V_{ball} = \frac{4}{3} \times 3.14\times 125$

$V_{ball} = \frac{1,570}{3}\: In^3$

$V_{box} =l^3$

$V_{box} =(10)^3$

$V_{box} =1000\: In^3$

Percentage of the space in the box occupied by the ball

$= \frac{V_{ball}}{V_{box} } \times 100$

$= \frac{\frac{1,570}{3}}{1000} \times 100$

$= \frac{1570}{3000} \times 100$

$= \frac{157}{3}$

$= 52.33\%$

5 0

2 years ago