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Hatshy [7]
2 years ago
15

Mathematics.................

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
8 0

Answer:

this Is 3 and the second one is also 3

zepelin [54]2 years ago
5 0

1/2 of 6 is 5.5

6 x 1/2 = 9

This might not be accurate. I understand the question, but at the same time I don't. Sorry.

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Which equation represents the situation?
Tomtit [17]

Answer:

y=720x+100.......................

5 0
3 years ago
Can someone please answer this question please answer it correctly and please show work please help me I need it
Sedbober [7]

Answer:

C

Step-by-step explanation:

- 2 - 5 would represent a negative start, and further decreasing. So, a situation to describe this could be:

The temperature was -2°C and has <em>decreased</em><em> </em>by 5°C.

7 0
3 years ago
Write the equation of the circle in general form. Show all of your work
finlep [7]
<h2>1. What are the center and equation of the circle?</h2>

In this exercise we have the general form of the equation of a circle, which is given by:

x^2+y^2+18x+4y+49=0

The ordinary equation of a circle is:

(x-h)^2+(y-k)^2=r^2 \\ \\ Developing \ this \ equation: \\ \\ x^2+y^2-2hk-2ky+h^2+k^2-r^2=0

But this can be written as:

x^2+y^2+Dx+Ey+F=0 \\ \\ D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

From the original equation we know that:

D=18, \ E=4, \ and \ F=49 \\ \\ So: \\ \\ h=-\frac{18}{2}=9, \ k=-\frac{4}{2}=2, \ and \ r=\sqrt{9^2+2^2-49}=6

Finally:

\boxed{CENTER: \ (h,k)=(9,2)} \\ \\ \boxed{RADIUS: \ 6}

<h2>2. Write the equation of the circle in general form.</h2>

We need to write this equation in the form:

x^2+y^2+Dx+Ey+F=0

Since:

D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

Then we need to find the center and radius in order to get D, E and F then. From the graph, it is easy to know that the center is (h,k)=(-3,4) and the radius is 2. Therefore:

D=-2(-3)=6, \ E=-2(4)=-8, \ and \ F=(-3)^2+(4)^2-(2)^2=21

Finally, the general form of the equation is:

\boxed{x^2+y^2+6x-8y+21=0}

<h2>3. Write the equation of the parabola</h2>

A parabola is the set of all points in a plane that are equidistant from  a fixed line called the directrix and a fixed point called the focus that does not lie on the line. Since the directrix is x=2 then this is a horizontal axis. So the standard for of the equation of a parabola that matches this form is:

(y-k)^2=4p(x-h) \ \ p \neq 0

The vertex is (h,k)=(-5,8) so our goal is to find p:

(y-8)^2=4p(x+5)

We can find the absolute value of p as follows:

\left|p\right|=2-(-5)=7

Since the directrix is to the left of the vertex, the parabola opens to the left and hence:

p.

Finally, the equation is:

(y-8)^2=4(-7)(x+5) \\ \\ \boxed{(y-8)^2=-28(x+5)}

8 0
3 years ago
Read 2 more answers
The equation of the cables for a suspension bridge is modeled by the equation
Murrr4er [49]

The lowest point of the cables above the bridge is 48 feet above the bridge.

The statement give us a parabola equation in <em>standard</em> form, the <em>vertical</em> distance of the <em>lowest</em> point above the bridge is determined by the y-coordinate of the vertex. Hence, the lowest point of the cables above the bridge is 48 feet above the bridge.

We kindly invite to check this question on parabolae: brainly.com/question/8495869

3 0
2 years ago
What is an equation of the line that passes through the point (-2,-3)(−2,−3) and is parallel to the line 5x+2y=14
Semmy [17]

Answer:

y=5/2x+2

Step-by-step explanation:

rearrage equation: y=5/2x-7

new slope is same: y=5/2x+b

substitue point (-2,-3):

-3=5/2(-2)+b

-3=-5+b

-3+5=b

2=b

5 0
2 years ago
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