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Hatshy [7]
3 years ago
15

Mathematics.................

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0

Answer:

this Is 3 and the second one is also 3

zepelin [54]3 years ago
5 0

1/2 of 6 is 5.5

6 x 1/2 = 9

This might not be accurate. I understand the question, but at the same time I don't. Sorry.

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In the right triangle shown m angle A =45° and AB=12 how long is BC?
viva [34]

Answer:

8.48 = x

Step-by-step explanation:

sin45 = x / 12

12sin45 = x

8.48 = x

6 0
3 years ago
Read 2 more answers
The given graph represents the function f(x) = 2(5)*x
Sauron [17]

Answer:

f(x) = 2(5)*x

y=(2)(5)x

Y=10x

Step-by-step explanation: is this steps help you

6 0
3 years ago
‹Gordon read 18 pages of a bookabout rockets in 40 minutes. whatwas the unit rate per hour?
ValentinkaMS [17]
I believe 9?
I'm not good at math
5 0
4 years ago
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Karen bakes cookies. She has observed that the number of cookies that turn out well in each batch varies with the size of the ba
mestny [16]

Substitute the values of the size of the 5 batches to the model.

For example

@x = 20

f(20) = 2*20 – 23 = 17

f(25) = 2*25 – 23 = 27

f(26) =29

f(27) = 31

f(34) = 45

 

Therefore the answer is the first choice (17, 27, 29, 31, 42)

6 0
4 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
4 years ago
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