I can’t see the pic sorry
F=9/5c+32
-31=9/5c+32
-63=9/5c
-35=c
Writing the two equations in full and subtracting R(x) from W(x) to arrive at D (x) gives the answer. This is shown below;
W(x) = 0.002x^3 - 0.01x^2 + 0x + 0
R (x) = 0x^3 + x^2 - 4x +13 -
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D(x) = 0.002x^3 -1.01x^2 + 4x - 13
Hello!
The formula for circumference is

and the formula for area of a circle is

. Armed with these formulas, we can begin to find the circumferences and areas of the circles.
20.
C =

C =

C =

C = 13(3.14)
C = 40.8
A =

A =

A =

A = 132.7
The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in

because the diameter is the radius × 2. For

we do need to divide the diameter by 2.]
C =

C = 49.3
A =

A =

A =

A = 193.5
The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².
And that is all there is to it. I hope this helps you! (:
Answer:
- -3/13 ≈ -1/4
- -6/11 ≈ -1/2
- -7/9 ≈ -3/4
Step-by-step explanation:
We'll drop all the minus signs, since they don't contribute anything but distraction.
When numerators or denominators are relatively large, changing their value by 1 unit will have a relatively small effect on the value of the fraction. For example, ...
3/13 ≈ 3/12 = 1/4
If we compare the decimal values of these fractions, we see that ...
3/13 ≈ 0.230769... (6-digit repeating decimal)
The closest of the offered "reasonable estimate" fractions is 1/4 = 0.25.
__
Likewise, 6/11 ≈ 6/12 = 1/2. In decimal, these fractions are ...
6/11 = 0.54... (2-digit repeat)
1/2 = 0.5
__
We can also increase or decrease both numerator and denominator by the same amount to get a fraction with nearly the same value. This works best when the numbers are larger.
7/9 ≈ 6/8 = 3/4 . . . . . . both numerator and denominator decreased by 1
In decimal, these are ...
7/9 = 0.7... (1-digit repeat)
3/4 = 0.75